Bài 1: Tính Nhanh a) \(11\frac{1}{4}-\left(2\frac{5}{7} 5\frac{1}{4}\right)\) b) \(\left(8\frac{5}{11} 3\frac{5}{8}\right)-3\frac{5}{11}\) c) \(-\frac{1}{4}.13\frac{9}{11}-0,25.6\frac{2}{11}\) d)\...

1

KS

Kawaii Sanae

11 tháng 4 2018

- Nhầm wall rồi bạn ey :vv

Bài 1: Tính Nhanha) \(11\frac{1}{4}-\left(2\frac{5}{7}+5\frac{1}{4}\right)\)b) \(\left(8\frac{5}{11}+3\frac{5}{8}\right)-3\frac{5}{11}\)c) \(-\frac{1}{4}.13\frac{9}{11}-0,25.6\frac{2}{11}\)d)\(\frac{4}{9}:\left(\frac{-1}{7}\right)+6\frac{5}{9}:\left(\frac{-1}{7}\right)\)Bài 2: Tìm Xa)\(X:8,25=\left(-2,2\right)\)b)\(-4\frac{1}{5}.X=2,25\)c) \(\left(\frac{2X}{5}-1\right):\left(-5\right)=\frac{1}{7}\)Làm chi tiết hộ em được ko ạ :"< Mai em kiểm tra bài này rùi, mà em ngu lắm...

HH

Hà Hương Ly

11 tháng 4 2018

2

TC

Trần Cao Vỹ Lượng

11 tháng 4 2018

a)\(11\frac{1}{4}-\left(2\frac{5}{7}+5\frac{1}{4}\right)\)

\(=\frac{45}{4}-\left(\frac{19}{7}+\frac{21}{4}\right)\)

\(=\frac{45}{4}-\left(\frac{76}{28}+\frac{147}{28}\right)\)

\(=\frac{45}{4}-\frac{223}{28}\)

\(=\frac{315}{28}-\frac{223}{28}\)

\(=\frac{23}{7}\)

b) \(\left(8\frac{5}{11}+3\frac{5}{8}\right)-3\frac{5}{11}\)

\(=\left(\frac{93}{11}+\frac{29}{8}\right)-\frac{38}{11}\)

\(=\left(\frac{744}{88}+\frac{319}{88}\right)-\frac{38}{11}\)

\(=\frac{1063}{88}-\frac{38}{11}=\frac{1063}{88}-\frac{304}{88}\)

\(=\frac{69}{8}\)

DE

Đ𝒂𝒏 𝑫𝒊ệ𝒑

19 tháng 3 2020

1a) \(11\frac{1}{4}-\left(2\frac{5}{7}+5\frac{1}{4}\right)\)

\(=11\frac{1}{4}-2\frac{5}{7}-5\frac{1}{4}\)

\(=11\frac{1}{4}-5\frac{1}{4}-2\frac{5}{7}\)

\(=6-2\frac{5}{7}=3\frac{2}{7}=\frac{23}{7}\)

2a) \(x\div8,25=\left(-2,2\right)\)

\(\Leftrightarrow x=-18,15\)

TL

tôi là ai nhỉ

7 tháng 4 2019

Tính nhanh :

A=\(21\frac{4}{11}-\left(1\frac{3}{5}+7\frac{4}{11}\right)\)

B=\(\left(7\frac{8}{9}+2\frac{3}{13}\right)-\left(4\frac{8}{9}-7\frac{10}{13}\right)\)

C= \(\frac{-3}{5}+\frac{2}{7}+\frac{-3}{7}\cdot\frac{3}{5}+\frac{-3}{7}\)

3

NM

Ngọc Mai

7 tháng 4 2019

\(A=21\frac{4}{11}-\left(1\frac{3}{5}+7\frac{4}{11}\right)\)

\(A=\frac{235}{11}-\left(\frac{8}{5}+\frac{81}{11}\right)\)

\(A=\left(\frac{235}{11}-\frac{81}{11}\right)+\frac{8}{5}\)

\(A=\frac{154}{11}+\frac{8}{5}\)

\(\Rightarrow A=\frac{78}{5}\)

NM

Ngọc Mai

7 tháng 4 2019

\(B=\left(7\frac{8}{9}+2\frac{3}{13}\right)-\left(4\frac{8}{9}-7\frac{10}{13}\right)\)

\(B=\left(\frac{71}{9}+\frac{29}{13}\right)-\left(\frac{44}{9}-\frac{101}{13}\right)\)

\(B=\left(\frac{71}{9}-\frac{44}{9}\right)+\left(\frac{29}{13}-\frac{101}{13}\right)\)

\(B=\frac{27}{9}+\frac{-72}{13}\)

\(B=3+\frac{-72}{13}\)

\(\Rightarrow B=\frac{-33}{13}\)

P/s: Hoq chắc :v

a) \(\frac{2}{5}+\left(-\frac{4}{3}\right)+\left(-\frac{1}{2}\right)\) b) \(\frac{5}{8}-\left(-\frac{2}{5}-\frac{3}{10}\right)\) c) \(\frac{1}{3}-\left[\left(-\frac{5}{4}\right)-\left(\frac{1}{4}+\frac{3}{8}\right)\right]\) d) \(\frac{2}{3}-4.\left(\frac{1}{2}+\frac{3}{4}\right)\) e) \(\left(-\frac{1}{3}+\frac{5}{6}\right).11-7\) f)...

CD

Ciin Deyy

15 tháng 8 2020

Bài 1: Tính bằng cách hợp lí: a, \(11\frac{1}{4}-\left(2\frac{5}{7}+5\frac{1}{4}\right)\)b, \(\left(8\frac{5}{11}+3\frac{5}{8}\right)-3\frac{5}{11}\)c, \(-\frac{1}{4}.13\frac{9}{11}-0,25.6\frac{2}{11}\)d, \(\frac{4}{9}:\left(-\frac{1}{7}\right)+6\frac{5}{9}:\left(-\frac{1}{7}\right)\)Bài 2: Tính bằng cách hợp lí( nếu...

0

NT

Nguyễn Tuyết Mai

30 tháng 3 2015

1

TV

tran van anh

30 tháng 3 2015

a) 11 1/4- 2 5/7 - 5 1/4

11 1/4 - 5 1/4 - 2 5/7

( 11 -5) + ( 1/4 -1/4) -2 5/7

6 +0 -2 5/7

6- 2 5/7

5+1 - 2 5/7

( 5-2) + ( 1-5/7)

3+( 7/7 -5/7)

3 + 2/7

3 2/7

3+

LD

linh dangthuy

27 tháng 7 2017

a)\(\frac{-1}{4}.13\frac{9}{11}-0,25.6\frac{2}{11}\)

b)\(\frac{4}{9}:\left(\frac{-1}{7}\right)+6\frac{5}{9}:\left(\frac{-1}{7}\right)\)

2

PT

Pham Thi Thanh Thuy

27 tháng 7 2017

a=-5

b=-49

TK

The Key Of Love

19 tháng 3 2020

Bạn tính dần

=> Kết quả

a, (-5)

b,(-49)

TM

The magic

2 tháng 7 2019

\(\frac{11^4.6-11^5}{11^4-11^5}:\frac{9^8.3-9^9}{9^8.5+9^8.7}\)

\(\frac{3}{5}:\left(\frac{-1}{5}-\frac{1}{6}\right)+\frac{3}{5}:\left(\frac{-1}{3}-1\frac{1}{15}\right)\)

\(\left(\frac{1}{2}-\frac{13}{14}\right):\frac{5}{7}-\left(-\frac{2}{21}+\frac{1}{7}\right):\frac{5}{7}\)

\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)

1

HH

Hoàng hôn ( Cool Team )

2 tháng 7 2019

a)\(\frac{11^4.6-11^5}{11^4-11^5}:\frac{9^8.3-9^9}{9^8.5+9^8.7}\)

\(=1.6:\frac{9^8.3-9^8.9}{9^8.\left(5+7\right)}\)

\(=6:\frac{9^8.\left(3-9\right)}{9^8.12}\)

\(=6:\frac{9^8.\left(-6\right)}{9^8.12}\)

\(=6:\left(-\frac{6}{12}\right)\)

\(=6:\left(-\frac{1}{2}\right)\)

\(=-12\)

b) 3/5 : ( -1/5-1/6)+3/5:(-1/3-16/15) ( mình chuyển về ps luôn )

=3/5: (-11/30) + 3/5 : (-7/5)

=3/5:[-11/30+(-7/5)]

=3/5:53/30

=18/53

c) (1/2-13/14):5/7-(-2/21+1/7):5/7

= -3/7:5/7-1/21:5/7

=(-3/7-1/21):5/7

=-10/21:5/7

=-2/3

câu b vá c mình làm tắt nha. chúc bạn học tốt

tìm phần nguyên\(A=\left(\frac{-5}{11}\right).\frac{7}{15}+\frac{11}{-5}.\frac{30}{33}\)\(B=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+....+\frac{1}{x.\left(x+1\right)}\)(x∈Z)\(C=\frac{1}{3}-\frac{3}{5}+\frac{5}{7}-\frac{7}{9}+\frac{9}{11}-\frac{11}{13}+\frac{11}{13}-\frac{9}{11}+\frac{7}{9}-\frac{5}{7}+\frac{3}{5}-\frac{1}{3}\)\(D=\frac{1}{3}-\left[\left(-\frac{5}{4}\right)-\left(\frac{1}{4}+\frac{3}{8}\right)\right]\)giúp mk nhé, mk tk, mk thanks...

F

Freya

6 tháng 9 2017

#Toán lớp 7

4

PT

Phương Thảo Linh 0o0

6 tháng 9 2017

\(A=\left(-\frac{5}{11}\right).\frac{7}{15}+\frac{11}{-5}.\frac{30}{33}\)

\(A=-\frac{7}{33}+-2\)

\(A=-\frac{73}{33}\)

[ A] = -2

F

Freya

6 tháng 9 2017

làm đc hết rùi phần b thui

QL

Quyên Lê

5 tháng 10 2018

...

#Toán lớp 7

0

NN

nguyen ngoc son

2 tháng 7 2020

1.thực hiện phép...

1

NL

Nguyễn Lê Phước Thịnh

2 tháng 7 2020

a) Ta có: \(\frac{-1}{12}-\left(2\frac{5}{8}-\frac{1}{3}\right)\)

\(=-\frac{1}{12}-\frac{21}{8}+\frac{1}{3}\)

\(=\frac{-6}{72}-\frac{189}{72}+\frac{24}{72}\)

\(=-\frac{19}{8}\)

b) Ta có: \(-1,75-\left(\frac{-1}{9}-2\frac{1}{18}\right)\)

\(=\frac{-7}{4}+\frac{1}{9}+\frac{37}{18}\)

\(=\frac{-63}{36}+\frac{4}{36}+\frac{74}{36}\)

\(=\frac{5}{12}\)

c) Ta có: \(\frac{2}{5}+\frac{-4}{3}+\frac{-1}{2}\)

\(=\frac{12}{30}+\frac{-40}{30}+\frac{-15}{30}\)

\(=-\frac{43}{30}\)

d) Ta có: \(\frac{3}{12}-\left(\frac{6}{15}-\frac{3}{10}\right)\)

\(=\frac{3}{12}-\frac{6}{15}+\frac{3}{10}\)

\(=\frac{15}{60}-\frac{24}{60}+\frac{18}{60}\)

\(=\frac{3}{20}\)

e) Ta có: \(\left(8\frac{5}{11}+3\frac{5}{8}\right)-3\frac{5}{11}\)

\(=\frac{93}{11}+\frac{29}{8}-\frac{38}{11}\)

\(=5+\frac{29}{8}=\frac{40}{8}+\frac{29}{8}=\frac{69}{8}\)

f) Ta có: \(\frac{4}{9}:\left(-\frac{1}{7}\right)+6\frac{5}{9}:\left(-\frac{1}{7}\right)\)

\(=\frac{4}{9}\cdot\left(-7\right)+\frac{59}{9}\cdot\left(-7\right)\)

\(=\left(-7\right)\cdot\left(\frac{4}{9}+\frac{59}{9}\right)=\left(-7\right)\cdot7=-49\)

g) Ta có: \(\frac{-1}{4}\cdot13\frac{9}{11}-0,25\cdot6\frac{2}{11}\)

\(=\frac{-1}{4}\cdot\frac{152}{11}+\frac{-1}{4}\cdot\frac{68}{11}\)

\(=\frac{-1}{4}\cdot\left(\frac{152}{11}+\frac{68}{11}\right)=-\frac{1}{4}\cdot20=-5\)

h) Ta có: \(5\frac{27}{5}+\frac{27}{23}+0,5-\frac{5}{27}+\frac{16}{23}\)

\(=\frac{52}{5}+\frac{27}{23}+\frac{1}{2}-\frac{5}{27}+\frac{16}{23}\)

\(=\frac{52}{5}+\frac{43}{23}+\frac{1}{2}-\frac{5}{27}\)

\(=\frac{64584}{6210}+\frac{11610}{6210}+\frac{3105}{6210}-\frac{1150}{6210}\)

\(=\frac{78149}{6210}\)

i) Ta có: \(\frac{3}{8}\cdot27\frac{1}{5}-51\frac{1}{5}\cdot\frac{3}{8}+19\)

\(=\frac{3}{8}\cdot\frac{136}{5}-\frac{3}{8}\cdot\frac{206}{5}+\frac{3}{8}\cdot\frac{152}{3}\)

\(=\frac{3}{8}\cdot\left(\frac{136}{5}-\frac{206}{5}+\frac{152}{3}\right)=\frac{3}{8}\cdot\frac{110}{3}\)

\(=\frac{55}{4}\)